Infendro/bytes.kt
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switch to signed-first approach
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It turns out signed math is more performant
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Infendro
2026-01-15 14:10:14 +01:00
parent d06e523914
commit ff0e17b5ad
35 changed files with 862 additions and 826 deletions
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57
src/commonMain/kotlin/com/infendro/bytes/longarray/Copy.kt Normal file
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package com.infendro.bytes.longarray
import com.infendro.bytes.ByteOrder
import com.infendro.bytes.ByteOrder.BIG_ENDIAN
import com.infendro.bytes.ByteOrder.LITTLE_ENDIAN
fun LongArray.copyInto(
destination: ByteArray,
destinationOffset: Int = 0,
startIndex: Int = 0,
endIndex: Int = size,
order: ByteOrder = BIG_ENDIAN,
) {
val length = endIndex - startIndex
require(length >= 0)
require(startIndex in 0..(size - length))
require(destinationOffset in 0..(destination.size - (length * 8)))
when (order) {
BIG_ENDIAN -> {
repeat(length) { i ->
val offset = destinationOffset + (i * 8)
val value = this[startIndex + i]
destination[offset] = (value shr 56).toByte()
destination[offset + 1] = (value shr 48).toByte()
destination[offset + 2] = (value shr 40).toByte()
destination[offset + 3] = (value shr 32).toByte()
destination[offset + 4] = (value shr 24).toByte()
destination[offset + 5] = (value shr 16).toByte()
destination[offset + 6] = (value shr 8).toByte()
destination[offset + 7] = value.toByte()
}
}
LITTLE_ENDIAN -> {
repeat(length) { i ->
val offset = destinationOffset + (i * 8)
val value = this[startIndex + i]
destination[offset] = value.toByte()
destination[offset + 1] = (value shr 8).toByte()
destination[offset + 2] = (value shr 16).toByte()
destination[offset + 3] = (value shr 24).toByte()
destination[offset + 4] = (value shr 32).toByte()
destination[offset + 5] = (value shr 40).toByte()
destination[offset + 6] = (value shr 48).toByte()
destination[offset + 7] = (value shr 56).toByte()
}
}
}
}
fun LongArray.copyInto(
destination: UByteArray,
destinationOffset: Int = 0,
startIndex: Int = 0,
endIndex: Int = size,
order: ByteOrder = BIG_ENDIAN,
) = copyInto(destination.asByteArray(), destinationOffset, startIndex, endIndex, order)