switch to signed-first approach
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/ test (pull_request) Successful in 2m47s
All checks were successful
/ test (pull_request) Successful in 2m47s
It turns out signed math is more performant
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@@ -2,32 +2,33 @@ package com.infendro.bytes.int
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import com.infendro.bytes.ByteOrder
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import com.infendro.bytes.ByteOrder.BIG_ENDIAN
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import com.infendro.bytes.uint.copyInto
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fun Int.copyInto(
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destination: UByteArray,
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destinationOffset: Int = 0,
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order: ByteOrder = BIG_ENDIAN,
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) = toUInt().copyInto(destination, destinationOffset, order)
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import com.infendro.bytes.ByteOrder.LITTLE_ENDIAN
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fun Int.copyInto(
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destination: ByteArray,
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destinationOffset: Int = 0,
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order: ByteOrder = BIG_ENDIAN,
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) = toUInt().copyInto(destination, destinationOffset, order)
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) {
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require(destinationOffset in 0..(destination.size - 4))
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fun IntArray.copyInto(
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when (order) {
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BIG_ENDIAN -> {
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destination[destinationOffset] = (this shr 24).toByte()
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destination[destinationOffset + 1] = (this shr 16).toByte()
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destination[destinationOffset + 2] = (this shr 8).toByte()
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destination[destinationOffset + 3] = this.toByte()
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}
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LITTLE_ENDIAN -> {
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destination[destinationOffset] = this.toByte()
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destination[destinationOffset + 1] = (this shr 8).toByte()
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destination[destinationOffset + 2] = (this shr 16).toByte()
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destination[destinationOffset + 3] = (this shr 24).toByte()
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}
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}
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}
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fun Int.copyInto(
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destination: UByteArray,
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destinationOffset: Int = 0,
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startIndex: Int = 0,
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endIndex: Int = size,
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order: ByteOrder = BIG_ENDIAN,
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) = asUIntArray().copyInto(destination, destinationOffset, startIndex, endIndex, order)
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fun IntArray.copyInto(
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destination: ByteArray,
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destinationOffset: Int = 0,
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startIndex: Int = 0,
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endIndex: Int = size,
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order: ByteOrder = BIG_ENDIAN,
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) = asUIntArray().copyInto(destination, destinationOffset, startIndex, endIndex, order)
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) = copyInto(destination.asByteArray(), destinationOffset, order)
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